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String copy in C

C program to copy a string using library function strcpy and without using strcpy.

String copy C program

#include <stdio.h>
#include <string.h>

int main()
{
  char source[1000], destination[1000];

  printf("Input a string\n");
  gets(source);

  strcpy(destination, source);

  printf("Source string: %s\n", source);
  printf("Destination string: %s\n", destination);

  return 0;
}

Output of program:
C program to copy a string output

Copy string in C without using strcpy

#include <stdio.h>

int main()
{
  int c = 0;
  char s[1000], d[1000] = "What can I say about my programming skills?";

  printf("Before copying, the string: %s\n", d);

  printf("Input a string to copy\n");
  gets(s);

  while (s[c] != '\0') {
    d[c] = s[c];
    c++;
  }

  d[c] = '\0';

  printf("After copying, the string: %s\n", d);

  return 0;
}

Output of the program:

Before copying, the string: What can I say about my programming skills?
Input a string to copy
My programming skills are improving.            
After copying, the string: My programming skills are improving.

Creating a function to copy a string

#include <stdio.h>

void copy_string(char [], char []);

int main() {
  char s[1000], d[1000];
   
  printf("Input a string\n");
  gets(s);

  copy_string(d, s);
  printf("The string: %s\n", d);

  return 0;
}

void copy_string(char d[], char s[]) {
  int c = 0;
   
  while (s[c] != '\0') {
    d[c] = s[c];
    c++;
  }
  d[c] = '\0';
}

C program to copy a string using pointers

Function to copy a string using pointers.

void copy_string(char *target, char *source) {
   while (*source) {
      *target = *source;
      source++;
      target++;
   }
   *target = '\0';
}
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