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Sum of n numbers in C

Sum of n numbers in C: This program adds n numbers which will be entered by a user. The user will enter a number indicating how many numbers to add and then the user will enter n numbers. We can do this by using or without using an array.

C program to sum n numbers using a for loop

#include <stdio.h>
 
int main()
{
  int n, sum = 0, c, value;
 
  printf("How many numbers you want to add?\n");
  scanf("%d", &n);
 
  printf("Enter %d integers\n", n);
 
  for (c = 1; c <= n; c++)
  {
    scanf("%d", &value);
    sum = sum + value;
  }
 
  printf("Sum of the integers = %d\n", sum);
 
  return 0;
}

You can use long int or long long data type for the variable sum.
Download Add n numbers program.

Output of program:
Add n numbers C program output

C program to calculate sum of n numbers using an array

#include <stdio.h>

int main()
{
   int n, sum = 0, c, array[100];

   scanf("%d", &n);

   for (c = 0; c < n; c++)
   {
      scanf("%d", &array[c]);
      sum = sum + array[c];
   }

   printf("Sum = %d\n", sum);

   return 0;
}

The advantage of using an array is that we have a record of the numbers entered and can use them further in the program if required but storing them requires additional memory.

C program for addition of n numbers using recursion

#include <stdio.h>

long calculate_sum(int [], int);

int main()
{
  int n, c, array[100];
  long result;

  scanf("%d", &n);

  for (c = 0; c < n; c++)
    scanf("%d", &array[c]);

  result = calculate_sum(array, n);

  printf("Sum = %ld\n", result);

  return 0;
}

long calculate_sum(int a[], int n) {
  static long sum = 0;

  if (n == 0)
    return sum;

  sum = sum + a[n-1];

  return calculate_sum(a, --n);
}

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