C program to check if a matrix is symmetric or not: we find the transpose of the matrix and then compare it with the original matrix. For a symmetric matrix A, AT = A.
C program to check if a matrix is symmetric or not
int main()
{
int m, n, c, d, matrix[10][10], transpose[10][10];
printf("Enter the number of rows and columns of matrix\n");
scanf("%d%d", &m, &n);
printf("Enter elements of the matrix\n");
for (c = 0; c < m; c++)
for (d = 0; d < n; d++)
scanf("%d", &matrix[c][d]);
for (c = 0; c < m; c++)
for (d = 0; d < n; d++)
transpose[d][c] = matrix[c][d];
if (m == n) /* check if order is same */
{
for (c = 0; c < m; c++)
{
for (d = 0; d < m; d++)
{
if (matrix[c][d] != transpose[c][d])
break;
}
if (d != m)
break;
}
if (c == m)
printf("The matrix is symmetric.\n");
else
printf("The matrix isn't symmetric.\n");
}
else
printf("The matrix isn't symmetric.\n");
return 0;
}